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 " " Given the Equation color(red)(y=f(x)=4x^2 A Quadratic Equation takes the form color(blue)(y=ax^2bxc Graph of a quadratic function forms a Parabola The coefficient of the color(red)(x^2 term (a) makes the parabola wider or narrow If the coefficient of the color(red)(x^2, term (a) is negative then the parabola opens down Let the focus and directrix of this particular parabola be Take a standard form of parabola equation ( x h) 2 = 4 p ( y k) In this equation, the focus is ( h, k p) Whereas the directrix is y = k p When at rest, the surface of mass of liquid is horizontal at PQ as shown in the figure A suitable rotation around the origin can thenOpens downward Move the y and 3 to the right, and then factor 2 out of the two x terms to get 2 ( x2 4 x) = – y 5 Complete the square in the parentheses, and add 8 to the right side Simplify and factor to get 2 ( x 2) 2 = –1 ( y – 5) Divide each side by 2 Solved Consider The Parabola Y 4x X2 A Find The Slope Chegg Com Y=x2-4x+2 par

The answer is, not really It is still always going to be implicit Given x = r*cos (θ) and y = r*sin (θ), the equation posted reduces to (r2 1)3 = r5 cos2 (θ) sin3 (θ) Thats about as simple as I could get it To the first order you can solve for θ to get ** θ = r 2/3 r 5/3 ** 11 Continue this thread level 2 mabufo 11 yr agoExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science Answer 1) C 2) (2,0) 3) 4) 5) c )S={(0,3)} 6) (0,2) 7) 8) Missing graph 9) Vertical line (check below) 10) B 11) Stepbystep explanation 1) Solving by the Addition/Elimination Method Firstly, let's reduce one variable by making some algebraic adjustments and then adding it up 2) Solving by Substitution MethodWhere y=x2 is plugged in the 2nd equation Find The Equation Of The Line Drawn Through The Point Of Intersection Of The Lines X 2y 3 0 And 2x 3y 4 0 And Passing Through T